∫etan−1x(1+x2)[(sec−1√1+x2)2+cos−1(1−x21+x2)]dx(x>0) equals to(where c is the constant of integration)

∫etan−1x(1+x2)[(sec−1√1+x2)2+cos−1(1−x21+x2)]dx(x>0) equal

1.	∫etan−1x(1+x2)[(sec−1√1+x2)2+cos−1(1−x21+x2)]dx(x>0) equals to(where c is the constant of integration)
Answer» $\int \frac{e^{{tan}^{- 1} x}}{(1 + x^{2})} [{({sec}^{- 1} \sqrt{1 + x^{2}})}^{2} + {cos}^{- 1} (\frac{1 - x^{2}}{1 + x^{2}})] d x (x > 0)$ equals to (where $c$ is the constant of integration)