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Answer» So frnd ur answer is --
For disproportionation reactions, use a TRICK to find equivalent mass; E = E1 + E2; where E1 and E2 are equivalent masses of oxidation and reduction HALF reactions of same element.
Now, find the n-factor(total change in oxidation number per molecule) and then equivalent mass = molar mass/n-factor.
So, when H3PO2 changes into PH3, oxidation state of phosphorous changes from +1 to -3 so as n-factor is 4. Also when H3PO2 changes into H3PO4, oxidation state of phosphorous changes from +1 to +5 so as n-factor is again 4.
Now equivalent mass of H3PO2, E =(M/4) + (M/4) = M/2
hope it helps U!!!☺
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