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Equivalent condictance of `BaCI_(2), H_(2)SO_(4)` and `HCI` are `x_(1) , x_(2)` and `x_(3) S cm^(2) "equiv"^(-1)` at infinite dilution , if specific condictance of structured `BaSO_(4)` solution is of `y S cm^(-1)` then `K_(p)` of `BaSO_(4)` isA. `(10^(3)y)/(2(x_(1) + x_(2)- 2x_(3)))`B. `(10^(6)y^(2))/((x_(1) + x_(2)- 2x_(3))^(2))`C. `(10^(6)y^(23))/(4(x_(1) x_(2)- 2x_(3))^(2))`D. `(x_(1) x_(2)- 2x_(3))/(10^(3)y^(2))` |
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Answer» Correct Answer - c `Delta_(BaSO_(4))^(@) = Delta_(BaCI_(2))^(@) + Delta_(H_(2)SO_(4))^(@) - 2 Delta_(HCI)^(@)` `= (x_(1) + x_(2) - 2x_(3))` `Delta_(BaSO_(4))^(@) = (1000 xx "sp. Conductance")/("solubility (in saturated solutions)")` `(x_(1) + x_(2) xx 2x_(3)) = (1000 y)/("solubility")` `:.` Solubilty of `BaSO_(4) = (1000y)/((x_(1)+x_(2) -2x_(3)))N` `= (1000y)/(2(x_(1)+x_(2)-2x_(3)))M` `BaSO_(4) rarr Ba^(2+) + SO_(4)^(2-)` `K_(sp) (BaSO_(4)) = [Ba^(2+)] [SO_(4)^(2-)] M^(2) = (10^(6)y^(2))/(4(x_(1)+x_(2)-2x_(3))^(2))` |
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