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.Equilibrium concentrations of A and B involved infollowing equilibrium are 0.01 M and 0.02 Mrespectively: A(g) B(g)If 0.01 M of A is added at equilibrium, thenat new equilibrium concentration of B will be(2) 2.67 x 10-2 M(1) 6.67 x 10-2 M(4) 1.33 x 10-1 M(3) 1.33 10-2 M |
| Answer» .Equilibrium concentrations of A and B involved infollowing equilibrium are 0.01 M and 0.02 Mrespectively: A(g) B(g)If 0.01 M of A is added at equilibrium, thenat new equilibrium concentration of B will be(2) 2.67 x 10-2 M(1) 6.67 x 10-2 M(4) 1.33 x 10-1 M(3) 1.33 10-2 M | |