Equation of the hyperbola with eccentricity 32 and foci at (±2, 0) is – InterviewSolution

1.	Equation of the hyperbola with eccentricity 32 and foci at (±2, 0) is(a) x24−y25=49(b) x29−y29=49(c) x24−y29=1(d) none of these
Answer» Equation of the hyperbola with eccentricity $\frac{3}{2}$ and foci at (±2, 0) is (a) $\frac{x^{2}}{4} - \frac{y^{2}}{5} = \frac{4}{9}$ (b) $\frac{x^{2}}{9} - \frac{y^{2}}{9} = \frac{4}{9}$ (c) $\frac{x^{2}}{4} - \frac{y^{2}}{9} = 1$ (d) none of these

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