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Equation of parabola whose focus is (0,0) and directrix is the straight line 3x-4 y +2=0

Answer» S =(0,0), eq of directrix= 3x-4y+2=0Let p (x,y) PM be the distancePM = | 3x-4y+2|/root under 3^2+(-4)^2By def of parabola PS^2=PM^2(x-0)^2+(y-0)^2=(3x-4y+2)^2/5^2x^2+y^2=9x^2+16y^2+4-24xy-16y+12xSolve this u get eq of parabola
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