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Equation of motion with all 3 methods all 3 equations mathematical y solved |
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Answer» v = u + atv² = u² + 2ass = ut + ½at² where, s = displacement; u = initial VELOCITY; v = final velocity; a = acceleration; t = TIME of motion. These equations are referred as SUVAT equations where SUVAT stands for displacement (s), initial velocity (u), final velocity (v), acceleration (a) and time (T) Derivation of the Equations of Motion v = u + at Let us begin with the first equation, v=u+at. This equation only talks about the acceleration, time, the initial and the final velocity. Let us assume a body that has a MASS “m” and initial velocity “u”. Let after time “t” its final velocity becomes “v” due to uniform acceleration “a”. Now we know that: Acceleration = Change in velocity/Time Taken Therefore, Acceleration = (Final Velocity-Initial Velocity) / Time Taken Hence, a = v-u /t or at = v-u Therefore, we have: v = u + at v² = u² + 2as We have, v = u + at. Hence, we can write t = (v-u)/a Also, we know that, Distance = average velocity × Time Therefore, for constant acceleration we can write: Average velocity = (final velocity + initial velocty)/2 = (v+u)/2 Hence, Distance (s) = [(v+u)/2] × [(v-u)/a] or s = (v² – u²)/2a or 2as = v² – u² or v² = u² + 2as s = ut + ½at² Let the distance be “s”. We know that Distance = Average velocity × Time. Also, Average velocity = (u+v)/2 Therefore, Distance (s) = (u+v)/2 × t Also, from v = u + at, we have: s = (u+u+at)/2 × t = (2u+at)/2 × t s = (2ut+at²)/2 = 2ut/2 + at²/2 or s = ut +½ at² |
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