Saved Bookmarks
| 1. |
Equation of a line passing through(1,2) and parallel to the line y = 3x - 1 is |
|
Answer» y=3x−1y=3x−1 =>3x−y−1=0=>3x−y−1=0 A line which is parallel to another will have same SLOPE. The slope of the line Ax+By+c=0Ax+By+c=0is given by −BA−BA Hence, a line parallel to the line Ax+By+C=0Ax+By+C=0is given by Ax+By+K=0Ax+By+K=0 =>3x−y+K=0=>3x−y+K=0is a line parallel to 3x−y−1=03x−y−1=0 It is given that the REQUIRED line PASSES through (0,0)(0,0) i.e. 3x−y+K=03x−y+K=0passes through (0,0)(0,0) =>3⋅0−0+K=0=>3⋅0−0+K=0 =>K=0=>K=0 =>3x−y=0=>3x−y=0 is the required line. or y=3xy=3xis the required line. |
|