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Equation of a circle which passes through (3, 6) and touches the axes is(a) x2 + y2 + 6x + 6y + 3 = 0(b) x2 + y2 – 6x – 6y – 9 = 0(c) x2 + y2 – 6x – 6y + 9 = 0(d) None of these |
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Answer» Equation of a circle which passes through (3, 6) and touches the axes is (a) x2 + y2 + 6x + 6y + 3 = 0 (b) x2 + y2 – 6x – 6y – 9 = 0 (c) x2 + y2 – 6x – 6y + 9 = 0 (d) None of these |
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