equal toThe value of(e)beereriNTSE STAGE 17. The value of(B) -1(C) 0(D

1.	equal toThe value of(e)beereriNTSE STAGE 17. The value of(B) -1(C) 0(D) abc(A) 1
Answer» we know that 1 ) x ^m / x^n = x ^ ( m -n ) 2 ) ( x^m )^n = x ^mn 3 ) x^0 = 1 4) x^m * x^n = x ^( m+ n ) Now , =(x^a/x^b)^1/ab( x^b /x^c)^1/bc(x^c/x^a)^1/ca = (x^a-b)1/ab(x^b-c)^1/bc(x^c-a)^1/ca = x^(a-b)/ab * x^(b-c)/bc * x^(c-a)/ca = x^[(a-b)/ab + (b-c)/bc + (c-a)/ca] = x^[c(a-b)/abc + a(b-c)/abc + b(c-a)/abc ] = x ^{ [c(a-b)+ a(b-c) + b(c-a) ]/abc } = x^ ( ac - bc + ab - ac + bc - ab ] /ABC = x^ 0/abc = x^0 = 1 Like my answer if you find it useful!

equal toThe value of(e)beereriNTSE STAGE 17. The value of(B) -1(C) 0(D) abc(A) 1

Answer»

we know that

1 ) x ^m / x^n = x ^ ( m -n )

2 ) ( x^m )^n = x ^mn

3 ) x^0 = 1

4) x^m * x^n = x ^( m+ n )

Now ,

=(x^a/x^b)^1/ab( x^b /x^c)^1/bc(x^c/x^a)^1/ca

= (x^a-b)1/ab(x^b-c)^1/bc(x^c-a)^1/ca

= x^(a-b)/ab * x^(b-c)/bc * x^(c-a)/ca

= x^[(a-b)/ab + (b-c)/bc + (c-a)/ca]

= x^[c(a-b)/abc + a(b-c)/abc + b(c-a)/abc ]

= x ^{ [c(a-b)+ a(b-c) + b(c-a) ]/abc }

= x^ ( ac - bc + ab - ac + bc - ab ] /ABC

= x^ 0/abc

= x^0

= 1

Like my answer if you find it useful!