1.

Equal moles of h2o and nacl are present in a solution hence molality of nacl solution is

Answer»

Consider ‘Y’ mol of water and ‘Y’ mol of NACL are mixed to prepare a SOLUTION.

1 mol of water contains 18 g

That means, Y mol of water contains 18Y g

Mass / Density = Volume

Density of water = 1

So, volume of Y mol water = 18Y / 1 = 18Y mL

That means Y mol of NaCl is dissolved in 18Y mL of water.

1 mol of NaCl contains 58.44 g

That means, Y mol of NaCl contains 58.44Y g

Molality can be CALCULATED as follows:

Molality = (weight of NaCl x 1000) / (Equivalent weight of NaCl x volume of water)

Substitute in EQUATION,

Molality = (58.44Y x 1000) / (58.44 x 18Y)

Molality = 55.56 M

Molality of NaCl solution is 55.56 M.



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