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Equal moles of h2o and nacl are present in a solution hence molality of nacl solution is |
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Answer» Consider ‘Y’ mol of water and ‘Y’ mol of NACL are mixed to prepare a SOLUTION. 1 mol of water contains 18 g That means, Y mol of water contains 18Y g Mass / Density = Volume Density of water = 1 So, volume of Y mol water = 18Y / 1 = 18Y mL That means Y mol of NaCl is dissolved in 18Y mL of water. 1 mol of NaCl contains 58.44 g That means, Y mol of NaCl contains 58.44Y g Molality can be CALCULATED as follows: Molality = (weight of NaCl x 1000) / (Equivalent weight of NaCl x volume of water) Substitute in EQUATION, Molality = (58.44Y x 1000) / (58.44 x 18Y) Molality = 55.56 M Molality of NaCl solution is 55.56 M. |
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