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Equal masses of `H_(2)O_(2)` and methane have been taken in a container of volume V at temperature `27^(@)C` in identical conditions. The ratio of the volumes of gases `H_(2) : O_(2)` : methane would beA. `8:16:1`B. `16:8:1`C. `16:1:2`D. `8:1:2` |
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Answer» Correct Answer - C Suppose mass of each of `H_(2), O_(2)` and `CH_(4)` taken =w g `w g H_(2)=(w)/(2)"mole", w g O_(2)=(w)/(32)"mole"`, `w g CH_(4)=(w)/(16)"mole"` As under identical conditions, volume are in the ratio of moles. Hence, volume of `H_(2) : O_(2): CH_(4)=(w)/(2) : (w)/(32) : (w)/(16)` `=(1)/(2) : (1)/(32) : (1)/(16)=16 : 1 : 2` |
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