1.

Enthalpy of combustion of propane,butane and pentane are -2220, -2878 , -3537 kJ/mol respectively. Order of chlorific value ( per gram) of fuel will be. 1. propane > Butane > pentane. 2. Butane > Pentane > propane. 3. Propane < butane < pentane. 4. pentane < butane < propane​

Answer»

The correct answer is option 3.Explanation:Calorific value of a SUBSTANCE is defined as amount of heat generated on COMBUSTION of a fixed amount of a substance. Generally expressed in JOULES per kilograms.Enthalpy of combustion of PROPANE = -2220 kJ/mol Mass of 1 mol = 44 gCalorific value of propane:Enthalpy of combustion of butane = -2878 kJ/mol Mass 1 mol = 58 gCalorific value of butane:Enthalpy of combustion of pentane = -3537 kJ/mol Mass of 1 mol = 72 gCalorific value of pentane :Order of calorific value ( per gram) of fuel will be:Propane < butane < pentane



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