Enthalpy change for the process, H2O(s)⇌H2O(l) is 6.01 kJ mol−1. T – InterviewSolution

1.	Enthalpy change for the process, H2O(s)⇌H2O(l) is 6.01 kJ mol−1. The entropy change for 1 mole of ice at its melting point will be
Answer» Enthalpy change for the process, $H_{2} O (s) ⇌ H_{2} O (l)$ is $6.01 k J m o l^{- 1} .$ The entropy change for 1 mole of ice at its melting point will be

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