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Energy of an electron in the ground state of the hydrogen atom is -2.18×10−18 J. The ionization enthalpy of atomic hydrogen is a×105 J/mol. Then ‘a′ is: (Take NA=6×1023)

Answer» Energy of an electron in the ground state of the hydrogen atom is -2.18×1018 J. The ionization enthalpy of atomic hydrogen is a×105 J/mol. Then a is: (Take NA=6×1023)


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