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Energy of an electron in the ground state of the hydrogen atom is `-2.18xx10^(-18)J`. Callate the ionisation enthalpy of atomic hydrogen in terms of `kJ mol^(-1)`. Hint: Apply the idea of mole concept to derive the answer. |
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Answer» The energy required to remove an electron in the ground state of hydrogen atom =-(its energy in the ground state)=-`(-2.18xx10^(-18))` `2.18xx10^(-18)` `:.` IE per mol of hydrogen atoms `=(2.18xx10^(-18)xx6.02xx10^(23))/(1000)kJ` `=13.12.36 kJ "mol"^(-1)` |
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