Energy of a Proton with a wavelength of 450 NM is

1.	Energy of a Proton with a wavelength of 450 NM is
Answer» Answer: 2.76ev Explanation: E = Energy (joules) H = PLANCK's constant (6.626 10^-34 J/s) c = the speed of light (2.997 10^8 m/s) lambda = the wavelength of light (convert to meters) Of course if you want the answer in electron volts (eV) you have to convert it later. So, E = (6.62610^-34 x 2.99710^8)/45010^-9 = 4.41310^-19 Joules 1 eV = 1.610^-19 Joules THEREFORE the energy of a PHOTON with a wavelength of 450 NM* = 2.76 eV i hope this will help you

Answer»

Answer:

2.76ev

Explanation:

E = Energy (joules)

H = PLANCK's constant (6.626 *10^-34 J/s)

c = the speed of light (2.997 *10^8 m/s)

lambda = the wavelength of light (convert to meters)

Of course if you want the answer in electron volts (eV) you have to convert it later.

So, E = (6.626*10^-34 x 2.997*10^8)/450*10^-9

= 4.413*10^-19 Joules

1 eV = 1.6*10^-19 Joules

THEREFORE the energy of a PHOTON with a wavelength of 450 NM

= 2.76 eV

i hope this will help you

Discussion