EMF of the following cell is 0.634 volt at 298 K Pt|H2 (1 atm)|H+(aq)| – InterviewSolution

1.	EMF of the following cell is 0.634 volt at 298 K Pt\|H2 (1 atm)\|H+(aq)\|\|Hg2+2 (aq. 1 N)\|Hg(l). The pH of anode compartment is : (Given, EoHg2+2\|Hg=0.28 and 2.303RTF=0.059)
Answer» EMF of the following cell is $0.634 v o l t$ at $298 K$ $P t \| H_{2} (1 a t m) \| H^{+} (a q) \| \| H g_{2}^{2 +} (a q . 1 N) \| H g (l)$ . The pH of anode compartment is : (Given, $E_{H g_{2}^{2 +} \| H g}^{o} = 0.28 and \frac{2.303 R T}{F} = 0.059$ )

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