1.

EMF of a cell whose half cells are given below is `Mg^(2+)+2e^(-)toMg(s),E=-2.37V` `Cu^(2+)+2e^(-)toCu(s),E=+0.33V`

Answer» Correct Answer - C
`E_(cell)^(o)=E_("cathode")^(o)-E_("anode"), " "E_(cell)^(o)=0.34-(-2.37)`
`E_(cell)^(o)=2.71V`


Discussion

No Comment Found

Related InterviewSolutions