1.

EMF of a cell in terms of reduction potential of its left and right electrodes is:-

Answer»

`E=E_("left")-E_("right")`
`E=E_("left")+E_(right)`
`E=E_(right)-E_("left")`
`E-(E_(right)+E_("left"))`

SOLUTION :(Reduction POTENTIAL of CATHODE)-(reduction potential of ANODE).


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