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Electrons give up energy at the rate of Rl^(2) per second to the thermal energy. What time scale would number associate with energy in problem (a) ? N = no of electron/ volume = 10^(29)//m^(3) , length of circuit = 10 cm , cross-section = A = (1 mm )^(2) |
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Answer» SOLUTION :Power dissipated, P = `I^(2) ` R `(E)/(l) = (1)^(2) xx6 ` `therefore (E)/(t) = 6 W` `therefore t = (E)/(6) = (2XX 10^(-17))/(6) "" [ because "K.E." = E]` `therefore t = (1)/(3)xx 10^(-17)` `therefore tapprox 0.33 xx 10^(-17) ` s `therefore t approx 3.3 xx 10^(-18) ` S |
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