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Electron in a sample of `H-` atoms make transitions from state `n=x` to some lower excited state. The emission spectrum from the sample is found to contain only the lines belonging to a particular series. If one of the photons had an energy of `0.6375 eV`. Then find the value of `x. [" Take " 0.6375eV=(3)/(4)xx0.85eV]`.A. 16B. 24C. 8D. 20 |
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Answer» Correct Answer - 3 We have, `" "DeltaE=(3)/(4)xx0.85eV` as energy `=0.6375` the photon will belong to brakett series ( as for brackett `0.31 le E le0.85)` `0.85xx(1-(1)/(4))=13.6((1)/(4^(2))-(1)/(n^(2)))` `0.85(1-(1)/(4))=(13.5)/(16)[1-((4)/(n))^(2)]" ":. (4)/(n)=(1)/(2)" "rArr" "n=8` |
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