1.

Electron configuration of an atom is 2, 8, 7 to which of the following elements would it bechemically similar? [ ]a) nitrogen(Z=7)b) fluorine(Z=9) c) phosphorous(Z=15) d) argon(Z=18)

Answer»

Dear STUDENT,

◆ Answer -

(b) Fluorine (Z=9)

EXPLANATION -

Given that electronic configuration of the UNKNOWN atom is 2, 8, 7.

Electronic configuration of Fluorine will be 2, 7.

As no of ELECTRONS in last orbit of unknown atom are same as that for fluorine, they will be chemically similar.

Thanks dear. Hope this HELPS you..



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