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Electrode potential data of few cells is given below. Based on the data, arrange the ions in increasing order of their reducing power :-Fe3+(aq) + e– → Fe2+(aq); E° = +0.77 VAl3+(aq) + 3e– → Al(s); E° = –1.66 VBr2(aq) + 2e– → 2Br–(aq); E° = +1.09 V(1) Br– < Fe2+ < Al(2) Fe2+ < Al < Br–(3) Al < Br– < Fe2+(4) Al < Fe2+ < Br– |
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Answer» Electrode potential data of few cells is given below. Based on the data, arrange the ions in increasing order of their reducing power :- Fe3+(aq) + e– → Fe2+(aq); E° = +0.77 V Al3+(aq) + 3e– → Al(s); E° = –1.66 V Br2(aq) + 2e– → 2Br–(aq); E° = +1.09 V (1) Br– < Fe2+ < Al (2) Fe2+ < Al < Br– (3) Al < Br– < Fe2+ (4) Al < Fe2+ < Br– |
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