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Ek samabahu prizm ekpristho rasmi ki apatan kon 30°.. another pritho ki patisarn kon 40°..so rasmi ki chuti kitni hogi ? |
Answer» Answer:The incidence angle is 48.59 degrees and angle of MINIMUM deviation is 36.98 degrees. Explanation: Refracting angle o f a prism A=60∘ and its REFRACTIVE INDEX is n=3/2. What is angle of incidence i to get minimum deviation. Also, find the minimum deviation. Assume the SURROUNDING medium to be air (n=1). We have, Angle of prism, A = 60 Refractive index, n = 3/2 For minimum deviation, the refractive index is given by : n=\dfrac{\sin (A+\delta _m)/2}{\sin A/2}n= sinA/2 sin(A+δ m
)/2
\delta_mδ m
is minimum deviation $$\begin{lgathered}\dfrac{3}{2}=\dfrac{\sin (60+\delta _m)/2}{\sin 60/2}\\\\\dfrac{3}{2}=\dfrac{\sin (60+\delta _m)/2}{\sin (30)}\\\\\dfrac{3}{4}=\sin(\dfrac{60+\delta _m}{2})\\\\\sin^{-1}(\dfrac{3}{4})=\dfrac{60+\delta _m}{2}\ ........(1)\\\\48.49=\dfrac{60+\delta _m}{2}\\\\\delta_m=36.98^{\circ}\end{lgathered}$$ We know that, angle of incidence is : $$i=\dfrac{A+\delta_m}{2}$$ |
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