efficiency of engine is 40%,at sink temperature is 27 degree celsius.if increase 10% efficiency,how much source temperature ?

efficiency of engine is 40%,at sink temperature is 27 degree celsius.i

1.	efficiency of engine is 40%,at sink temperature is 27 degree celsius.if increase 10% efficiency,how much source temperature ?
Answer» Engine in Thermodynamics:efficiency η = 40%T₁ = 27 degC = 300 °K = heat sink temperature T₂ = ? = temperature of the heat source 40 % = η = 1 - T₁ / T₂ = 1 - 300 / T₂ T₂ = 300 / 0.60 = 500 °K = 227 °C If the efficiency is increased by 10% to 50 % Then 1 - T₁ / T₂ = η = 0.50 T₂ = 2 T₁ = 600 °K = 327 °CThus the temperature of the source is to be increased by 100 °C to INCREASE the efficiency by 10 % for an ideal Carnot MACHINE.

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efficiency of engine is 40%,at sink temperature is 27 degree celsius.if increase 10% efficiency,how much source temperature ?

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