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1.	[ ee L 9kua3l+m A o)othon . thon -?J“A e 2_} ksto [६ 15 (७+एफैव -
Answer» we know, let us suppose two roots as x1 & x2 ATQ, x1=(-x2) sum of roots, x1+x2=(-b/a) =(8k-8)/4=2k-1. (x1=-x2) now, 2k-1=0 k=1/2(ans) So, the other equation isx^2 + 3x -18=0x^2 + 6x - 3x - 18=0x(x+6)-3(x+6)=0(x-3)(x+6)=0x=3,-6

[ ee L 9kua3l+m A o)othon . thon -?J“A e 2_} ksto [६ 15 (७+एफैव -

Answer»

we know,

let us suppose two roots as x1 & x2

ATQ, x1=(-x2)

sum of roots,

x1+x2=(-b/a)

=(8k-8)/4=2k-1. (x1=-x2)

now, 2k-1=0

k=1/2(ans)

So, the other equation isx^2 + 3x -18=0x^2 + 6x - 3x - 18=0x(x+6)-3(x+6)=0(x-3)(x+6)=0x=3,-6