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Earth revolves around the sun at 30 kms^(-1) calculated the kinetic energy of the Earth.What is the total energy of the Earth in that case? Is the total energy positive?Give reasons.(Potential energy of earth = -49.84xx10^32) |
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Answer» Solution :MASS of the Earth`M_(E) = 5.9 xx10^(24 kg` Speedof the Earth rovolves around the sun `V_(E) = 30 " K ms"^(-1)` Kinectic energy of Earth `E_(K ) = 1/2 M_(E) V_(E)^(2)` `E_(K) = 1/2 xx 5.9 xx10^(24) xx (30 xx10^(3))^(2)` ` = 1/2 xx 5310 xx10^(30) = 2655 xx10^(30)` `E_(K) = 2.655 xx10^(33) ` joule (or)J TOTAL energyof theEarth , E = Kinetic energy + Potential energy ` = 1/2 MV^(2) (-(GM_(1)M_(2))/(R^(2)))` ` = 2.655xx10^(33)+(-4.985 xx10^(33))` ` = 2.655 xx10^(33) - 4.985 xx10^(33)` `E = - 2.33 xx10^(33) ` joule (or) J |
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