Each of two men A and B is carrying a source of sound of frequency n . If A approaches B with a velocity u how many beats per second will be heard by B ? (Velocity of sound = c)

Each of two men A and B is carrying a source of sound of frequency n .

1.	Each of two men A and B is carrying a source of sound of frequency n . If A approaches B with a velocity u how many beats per second will be heard by B ? (Velocity of sound = c)
Answer» Solution :Apparent frequency , n. ` (C + u_(0))/(c- u_(5)) xx n` The distance between A and B is dacreasing . So , the velocity of the listener ` u_(0) ` and that of the source ` u_(s) ` , are both positive When B is the listener, velocity of the listener, ` u_(0)=0 `, Velocity of the source ` A , u_(s)= u ` So, ` n_(8) = (c) /(c-u) xxn ` Evidently, ` n_(8) GT n` ` therefore ` Number of beats PER SECOND ` therefore ` Number of beats per second ` n_(g) - n = ((c)/(c- u) -1)xx n = (u)/(c-u) n`