Each of two men A and B is carrying a source of sound of frequency n . If A approaches B with a velocity u how many beats per sound will be heard by A and B

Each of two men A and B is carrying a source of sound of frequency n .

1.	Each of two men A and B is carrying a source of sound of frequency n . If A approaches B with a velocity u how many beats per sound will be heard by A and B
Answer» Solution :APPARENT frequency , n. ` (C + u_(0))/(c- u_(5)) XX n` The distance between A and B is dacreasing . So , the velocity of the listener ` u_(0) ` and that of the source ` u_(s) ` , are both positive When A is the listener, velocity of the listener, ` u_(0) = u` , Velocity of the source ` B , u_(s) = 0 ` So, ` n_(A) = (c + u)/(c) xx n ` Evidently , ` n_(A) GT n` ` thereforeNumber of beats per socond ` = n_(A) - n = ((c + u)/(c) - 1) xx n = u/c n ` .