1.

each of equal sides of an isotope angle is 4 cm greater than its height if the base of the triangle is 24 cm calculate the perimeter and the area of the triangle​

Answer»

Let the congruent side of the isosceles TRIANGLE be a and the HEIGHT be h.

Given a=h+4

Since the height of the triangle, divides it into two RIGHT angled triangles,

a

2

=h

2

+(

2

b

)

2

=>(h+4)

2

=h

2

+12

2

h

2

+16+8h=h

2

+144

8h=128

h=16cm

a=20cm

Perimeter of the triangle = Sum of all sides =a+a+b=20+20+24=64cm

Area of triangle =

2

1

× base × height =

2

1

×24×16=192 sq CM


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