Each interior angle of a polygon is 108 find the number of sides of po

1.	Each interior angle of a polygon is 108 find the number of sides of polygon
Answer» If it is a regular POLYGON, then each interior ANGLE = (n-2) * 180/n $\frac{(n-2)180}{n}$ = 108 (n-2)180 = 108n (n-2)5 = 3*n 5n-10 = 3n 2n = 10 n=5 Since angle is 108 DEGREES, NUMBER of sides will be 5. Regards, KKKoppu

Each interior angle of a polygon is 108 find the number of sides of polygon

Answer»

If it is a regular POLYGON, then

each interior ANGLE = (n-2) * 180/n

$\frac{(n-2)*180}{n}$ = 108

(n-2)*180 = 108*n

(n-2)*5 = 3*n

5n-10 = 3n

2n = 10

n=5

Since angle is 108 DEGREES, NUMBER of sides will be 5.

Regards,

KKKoppu

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Each interior angle of a polygon is 108 find the number of sides of polygon

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