e shape of a cylinder surmounted by a conical top ofndIn fig. 5, a ten

1.	e shape of a cylinder surmounted by a conical top ofndIn fig. 5, a tent is in thsame diameter. If the height and diameter of cylindrical part are 2.1 m a3 m respectively and the slant height of conical part is 2.8 m, find the cost ocanvas needed to make the tent if the canvas is avaき500/sq.metre. (Use π=ー)s is available at the rate of2.1Figure 5
Answer» Given: Height (h) of the cylindrical part = 2.1 m Diameter of the cylindrical part = 3 m Radius of the cylindrical part = 3/2 m Slant height (l) of conical part = 2.8 m Total canvas used = CSA of conical part + CSA of cylindrical part = πrl + 2πrh = πr(2h+l) = (22/7)×3/2(2×2.1+2.8) = (22/7)×3/2(4.2+2.8) = (22/7)×3/2(7) = 11×3 = 33 m² Cost of 1 m² canvas = ₹ 500 Cost of 44 m² canvas = 33 × 500 = 16500 The cost of Canvas needed to make the tent= ₹ 16500 Hence, it will cost ₹ 16500 for making such a tent. Like my answer if you find it useful!

e shape of a cylinder surmounted by a conical top ofndIn fig. 5, a tent is in thsame diameter. If the height and diameter of cylindrical part are 2.1 m a3 m respectively and the slant height of conical part is 2.8 m, find the cost ocanvas needed to make the tent if the canvas is avaき500/sq.metre. (Use π=ー)s is available at the rate of2.1Figure 5

Answer»

Given:

Height (h) of the cylindrical part = 2.1 m

Diameter of the cylindrical part = 3 m

Radius of the cylindrical part = 3/2 m

Slant height (l) of conical part = 2.8 m

Total canvas used = CSA of conical part + CSA of cylindrical part

= πrl + 2πrh

= πr(2h+l)

= (22/7)×3/2(2×2.1+2.8)

= (22/7)×3/2(4.2+2.8)

= (22/7)×3/2(7)

= 11×3

= 33 m²

Cost of 1 m² canvas = ₹ 500

Cost of 44 m² canvas = 33 × 500 = 16500

The cost of Canvas needed to make the tent= ₹ 16500

Hence, it will cost ₹ 16500 for making such a tent.

Like my answer if you find it useful!