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E=mc^2 or, m=E/c^2 KE=1/2mv^2 or, m=2KE/v^2 2KE/v^2=E/c^2 When v=c then 2KE=E So, can we say that the kinetic energy of a body is half of the energy when it travels at the speed of light?

Answer» E=mc^2 or, m=E/c^2
KE=1/2mv^2 or, m=2KE/v^2
2KE/v^2=E/c^2
When v=c then 2KE=E
So, can we say that the kinetic energy of a body is half of the energy when it travels at the speed of light?


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