E is a point on the side bc of a triangle ABC such that the perpendicu

1.	E is a point on the side bc of a triangle ABC such that the perpendicular from E on the sides Ab and ac are equal show that ae bisects
Answer» ONG>Step-by-step explanation: $\huge\mathfrak\green{\bold{\underline{☘{ ℘ɧεŋσɱεŋศɭ}☘}}}$ $\red{\bold{\underline{\underline{QUESTION:-}}}}$ Q:-solve and verify the equation $\frac{1}{<klux>3</klux>} x - 4 = x - ( \frac{1}{2} + \frac{x}{ 3} )$ $\huge\tt\underline\blue{Answer }$ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _✍️ ══════════XXX═════════════ $⟹ \frac{1}{3} x - 4 = x - ( \frac{1}{2} + \frac{x}{3} )$ $⟹ \frac{x}{3} - 4 = x - ( \frac{3 + 2x}{6} )$ $⟹ \frac{x - 12}{3} = x - ( \frac{2x + 3}{6} )$ $⟹ \frac{x - 12}{3} = x - \frac{2x - 3}{6}$ $⟹ \frac{x - 12}{3} = \frac{6x - 2x - 3}{6}$ $⟹ \frac{x - 12}{3} = \frac{4x - 3}{6}$ cancelling 6( R.H.S) By 3 From L.H.S $⟹ \frac{x - 12}{1} = \frac{4x - 3}{2}$ $⟹2(x - 12) = 4x - 3$ $⟹2x - 24 = 4x - 3$ $⟹ - 24 + 3 = 4x - 2x$ $⟹ - 21 = 2x$ $⟹x = - \frac{21}{2}$ CHECK:- $⟹ \frac{ - \frac{21}{2} }{3} - 4 = - \frac{21}{2} - ( \frac{1}{2} + ( - ) \frac{ \frac{21}{2} }{3} )$ $⟹ - \frac{21}{6} - 4 = - \frac{21}{2} - ( \frac{1}{2} - \frac{21}{6} )$ $⟹ - \frac{7}{2} - 4 = - \frac{21}{2} - ( \frac{1}{2} - \frac{7}{2} )$ $⟹ \frac{ - 7 - 8}{2} = - \frac{21}{2} - ( - \frac{6}{2} )$ $⟹ - \frac{15}{2} = - \frac{21}{2} - ( - 3)$ $⟹ - \frac{15}{2} = - \frac{21}{2} + 3$ $⟹ - \frac{15}{2} = \frac{ - 21 + 6}{2} = - \frac{15}{2}$ THEREFORE,L.H.S=R.H.S VERIFIED✔️ ══════════XXX═════════════ HOPE IT HELPS YOU.. _____________________ THANKYOU:)