e(cos2x+cos4x+cos6x+⋯∞)loge2 satisfies the equation t2–9t+8=0, t – InterviewSolution

1.	e(cos2x+cos4x+cos6x+⋯∞)loge2 satisfies the equation t2–9t+8=0, then the value of 2sinxsinx+√3cosx,(0<x<π2) is :
Answer» $e^{({cos}^{2} x + {cos}^{4} x + {cos}^{6} x + \dots \infty) {log}_{e} 2}$ satisfies the equation $t^{2} - 9 t + 8 = 0,$ then the value of $\frac{2 sin x}{sin x + \sqrt{3} cos x}, (0 < x < \frac{π}{2})$ is :

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