1.

e ange ot elevation of the top of a verticai tower from a puint on the ground is 60From another peitt 10 tm vertically above the first, ils angle of elevation is45°. Pini theheight of the tower

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Answer:

Step-by-step explanation:

let height of tower = x + 10m

let dist. between base of tower and obs. pt. = y

at first angle it makes with ground = 60 degree

tan(60) = sqrt{3} = (x + 10)/y . . . . . . (eq 1)

next angle = 45 degree

pt is 10 m above the ground

tan(45)= 1 = x/y

:. x=y . . . . . . . . . (eq. 2)

substituting value of y in eq. 1

x + 10 = 1.732 x

:. x = 13.66



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