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dy-xa2 dy |
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Answer» y-x dy/dx=a(y2+dy/dx) dy/dx (a+x)=y-ay2 dy/(y-ay2) =dx/(a+x) intigrate both side ∫dy/(y-ay2) =∫dx/(a+x) ∫{1/y + a/(1-ay) }dy =∫dx/(a+x) ln|y| -ln|1-ay| +c=ln|x+a| ln(x+a)(1-ay)/y =c or(x+a)(1-ay)/y =C1 |
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