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dx/√2ax-x^2=a^nsin^-1[x/a-1].The value of n is?you may use dimensional analysis to solve the problem. And:- the value of n is 0 but how ?

Answer» dx/√2ax-x^2=a^nsin^-1[x/a-1].The value of n is?you may use dimensional analysis to solve the problem.

And:- the value of n is 0 but how ?


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