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During compression of a spring the work done is 10 kJ and 2 kJ escaped to the surroundings as heat. The change in internal energy, ΔU (in kJ) is : (1) 12 (2) –8 (3) 8 (4) –12 |
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Answer» Correct option (3) 8 Explanation: Work done on system = +10 kT Heat escaped = –2kI ΔU = q + w = 10 – 2 = 8 KJ |
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