During an experiment, an idea/gas is found to obey an additional law VP^(2) = constant . The gas is initially at temperature T and volume V. What will be the temperature of the gas when it expands to a volume 2 V?

During an experiment, an idea/gas is found to obey an additional law V

1.	During an experiment, an idea/gas is found to obey an additional law VP^(2) = constant . The gas is initially at temperature T and volume V. What will be the temperature of the gas when it expands to a volume 2 V?
Answer» <P> Solution :According to the given problem `VP^(2)` =K. constant. So the gas equation PV = nRT in the light of above (eliminating P) YIELDS `((K)/(sqrt(V))) V = nRt , `i.e., `sqrt(V)= (nR)/(K ) T ` `therefore sqrt((V_(1))/(V_(2))) = ((T_(1))/(T_(2)))," i.e., " sqrt((V)/(2V)) = (T)/(T^(1))` or `T^(1) = (sqrt(2))T `