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during a year the population of a town increased by 8% and during the next year the population decreased by 8%if the total population is 9936until end of the second year what was the population of the first yearanswer |
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Answer» <P>Answer: Present Population of the Town(A) = 15435. Rate of Increment(R%) = 5%. TIME(n) = 2 years. Now, Using the FORMULA, Present Population = Population n years ago × [1 + r/100]ⁿ 15435 = P [1 + 5/100]² 15435 = P[ 1 + 1/20]² 15435 = P[21/20]² 15435 = P [441/400] ⇒ P = 15435 × 400/441 ⇒ P = 35 × 400 ⇒ P = 14000 ∴ Population of the town 2 years ago is 14000. |
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