1.

during a year the population of a town increased by 8% and during the next year the population decreased by 8%if the total population is 9936until end of the second year what was the population of the first yearanswer ​

Answer»

<P>Answer:

Present Population of the Town(A) = 15435.

Rate of Increment(R%) = 5%.

TIME(n) = 2 years.

Now, Using the FORMULA,

 Present Population = Population n years ago × [1 + r/100]ⁿ

 15435 = P [1 + 5/100]²

15435 = P[ 1 + 1/20]²

15435 = P[21/20]²

15435 = P [441/400]

⇒ P = 15435 × 400/441

⇒ P = 35 × 400

⇒ P = 14000

∴ Population of the town 2 years ago is 14000.



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