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During a cyclic process, a heat engine absorbs 500 J of heat from a hot reservoir, does work and ejects an amount of heat 300 J into the surroundings (cold reservoir). Calculate the efficiency of the heat engine? |
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Answer» Solution :The efficiency of heat engine is given by `eta=1-(Q_(L))/(Q_(H))` `eta=1-(300)/(500)=1-(3)/(5)` `eta=1-0.6=0.4` The heat engine has `40%` efficiency, implying that this heat engine converts only `40%` of the INPUT heat into WORK. |
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