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During a cycle race, two persons A & B moving with velocity 16 m/s & 12 m/s respectively. At t=0, B observes A, 10 m ahead of him, in order to win the race they start acceleratingat 1 m/s2 and 2 m/s respectively. Unfortunately both finish simultaneously. The time(in sec) at which they finish the race is euqalto (t = 10 k), then value of k is : |
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Answer» During a cycle race, TWO persons A & B moving with velocity 16 m/s & 12 m/s respectively. At t=0, B observes A, 10 m AHEAD of him, in order to win the race they start accelerating at 1 m/s2 and 2 m/s respectively. both FINISH simultaneously in time = 10k secs To Find : value of kSolution:A Velocity = 16 m/sacceleration = 1 m/s²B Velocity = 12 m/sacceleration = 2 m/s² B observes A, 10 m ahead of him=> Distance covered by B = Distance covered by A + 10time = 10 k S = ut + (1/2)at²=> 12*10k + (1/2)(2)(10k)² = 16*10k + (1/2)(1)(10k)² + 10 => 120k + 100k² = 160k + 50k² + 10=> 50k² -40k - 10 = 0 => 5k² -4k - 1 = 0 => 5k² -5k + 1k - 1 = 0 => 5k(k - 1) + 1(k - 1) = 0=> (5k + 1)(k - 1) = 0=> k = 1 value of k = 1Learn More:An auto A is moving at 6m/s and accelerating at 1.5m/s2 to overtake ... brainly.in/question/22420842in a certain system of absolute units the acceleration produced by ... brainly.in/question/10736807 |
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