dtionation | Cue t6om ciimuy o Sioma (keLaneacocte Ak Mpcod by 2Se Yon

1.	dtionation \| Cue t6om ciimuy o Sioma (keLaneacocte Ak Mpcod by 2Se Yonlta dne itsnual Apcecl Blavd 436 usual Speasds\| Ay NI
Answer» Given: Late = 30 min Distance = 1500 km Speed increase = 100 km / hr To find: The usual speed. Solution: By formula, Speed = Distance / Time Since the time is unknown, Consider x for time, Speed original = 1500 / x Time taken = ( x - 1 / 2 ) Therefore, Substituting the value of x, Speed new = 1500 / (x - 1/2) Speed New - Speed original = 100 ( 1500 / ( x - 1 / 2 ) ) - ( 1500 / x ) = 100 150 ( ( 10 / x - 1 / 2 ) - 10 / x = 100 30 x -30 x +15 = 2x^2 - x 15 = 2x^2 - x 2x^2 - x -15 = 0 Solving, x = -5/2 x = 3 As time cannot be negative, The usual time taken by the plane is 3 hr Speed original = ( 1500 / 3 ) = 500 km / hr Hence, the usual speed of the plane is 500 km / hr

dtionation | Cue t6om ciimuy o Sioma (keLaneacocte Ak Mpcod by 2Se Yonlta dne itsnual Apcecl Blavd 436 usual Speasds| Ay NI

Answer»

Given:

Late = 30 min

Distance = 1500 km

Speed increase = 100 km / hr

To find:

The usual speed.

Solution:

By formula,

Speed = Distance / Time

Since the time is unknown,

Consider x for time,

Speed original = 1500 / x

Time taken = ( x - 1 / 2 )

Therefore,

Substituting the value of x,

Speed new = 1500 / (x - 1/2)

Speed New - Speed original = 100

( 1500 / ( x - 1 / 2 ) ) - ( 1500 / x ) = 100

150 ( ( 10 / x - 1 / 2 ) - 10 / x = 100

30 x -30 x +15 = 2x^2 - x

15 = 2x^2 - x

2x^2 - x -15 = 0

Solving,

x = -5/2

x = 3

As time cannot be negative,

The usual time taken by the plane is 3 hr

Speed original = ( 1500 / 3 ) = 500 km / hr

Hence, the usual speed of the plane is 500 km / hr