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Dry air was passed through a solution containing 20 g of a substance in 100.0 g of water and then through pure water. The loss in mass of the solution was 3 g and that of pure water was 0.06 g. Calculate the molar mass of the substance. |
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Answer» Dry air was passed through a solution containing 20 g of a substance in 100.0 g of water and then through pure water. The loss in mass of the solution was 3 g and that of pure water was 0.06 g. Calculate the molar mass of the substance. |
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