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Driver expression for acceleration due to gravity above the surface of Earth |
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Answer» Answer: let we CONSIDER, radius of earth R and mass is M and we know that acceleration due to gravity at surface G=R2GM ---- (i) G is universal gravitational CONSTANT. consider, a mass m is at above the earth at height h and g′ is acceleration due to gravity at height h. Therefore, g′=(R+h)2GM ----- (ii) divide, (ii) by (i) gg′=(R+h)2R2 g′=(R+h)2gR2 For h<< g′=g(1−R2h) Explanation: THANK UU |
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