1.

Driver expression for acceleration due to gravity above the surface of Earth​

Answer»

Answer:

let we CONSIDER,

radius of earth R and mass is M 

and we know that acceleration due to gravity at surface 

G=R2GM  ----   (i)

G is universal gravitational CONSTANT

consider, a mass m is at above the earth at height h and g′ is acceleration due to gravity at height h.

Therefore,  g′=(R+h)2GM -----  (ii)

divide, (ii) by (i)

gg′=(R+h)2R2

g′=(R+h)2gR2

For h<<

g′=g(1−R2h)

Explanation:

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