1.

Drive the following relation for kinetic energy ?

Answer»
k.e = \frac{ {mv}^{2} }{2} \\ k.e = \frac{ {mv}^{2} }{2} \times \frac{m}{m} \\ k.e = \frac{ {m}^{2} {v}^{2} }{2m} \\ k.e = \frac{ {(mv)}^{2} }{2m} \\ k.e = \frac{p}{2m}


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