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Draw the molecular structures of the following compounds : (i) N_(2)O_(5) "" (ii) XeOF_(4) Explain the following observations : (i) Sulphur has a greater tendency for catenation then oxygen. (ii) ICI is more reactive than I_(2). (iii) Despite lower value of its electron gain enthalpy with negative sing , fluorine (F_(2)) is a stronger oxidising agent than Cl_(2). |
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Answer» Solution :(b) (i) Due to small size of oxygen, lone pair of electron on oxygen ATOM repel the bond pair of O-O bond to greater extent than the lone pairs of electrons on the S atom is S-S bond . Hence S-Sbond is much stronger and hence much stronger tendency of for catenation than O (ii) ICI is more reactive than `I_(2)` because `I-Cl` bond is weaker than I-I bond because of less effective OVERLAPPING between orbitals of dissimilar atoms than those between similar atoms Consequently , ICI breaks easily to form halogen atoms which readily BRING about the reactions. (iii) It is due to Low enthalpy of dissociation of F-F bond . HIGH hydration enthalpy of `F^(-)`. |
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