1.

Draw the graph of y=3x+2. From the graph ,find the value of x if y=-1. Please Help fast...

Answer»

Gɪᴠᴇɴ :

Linear equation,

➢ \begin{gathered}\bf\red{\:y\:=\:3 \: <klux>X</klux> \: + \: 2} \\ \end{gathered}

❶ SUBSTITUTING 'x = 0' in the GIVEN equation, we get

\begin{gathered}:\implies\:\:\sf{\:y\:=\:3 \times 0 + 2} \\ \end{gathered}

\begin{gathered}:\implies\:\:\sf{\:y\:=\: 2} \\ \end{gathered}

❷ Substituting 'x = 1' in the given equation, we get

\begin{gathered}:\implies\:\:\sf{\:y\:=\:3 \times 1 + 2} \\ \end{gathered}

\begin{gathered}:\implies\:\:\sf{\:y\:=\:3 + 2} \\ \end{gathered}

\begin{gathered}:\implies\:\:\sf{\:y\:=\:5} \\ \end{gathered}

❸ Substituting 'x = 2' in the given equation, we get

\begin{gathered}:\implies\:\:\sf{\:y\:=\:3 \times 2 + 2} \\ \end{gathered}

\begin{gathered}:\implies\:\:\sf{\:y\:=\:6 + 2} \\ \end{gathered}

\begin{gathered}:\implies\:\:\sf{\:y\:=\:8} \\ \end{gathered}

Hᴇɴᴄᴇ,

➢ PAIR of points of the given equation are shown in the below table.

\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf 2 \\ \\ \sf 1 & \sf 5 \\ \\ \sf 2 & \sf 8 \end{array}} \\ \end{gathered}

➢ Now draw a graph using the points (0 , 2), (1 , 5) & (2 , 8)

➢ See the attachment graph.

\tt \ \: : ⟼ So, \: when \: y \: = - 1 \: then \: x = - 1


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